1/x+2+3/x^2-4=2/2-x

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Solution for 1/x+2+3/x^2-4=2/2-x equation: 



1/x+2+3/x^2-4=2/2-x

We move all terms to the left:

1/x+2+3/x^2-4-(2/2-x)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: 2-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-2

x!=-2/1

x!=-2

x∈R



We add all the numbers together, and all the variables

1/x+3/x^2-(-1x+1)+2-4=0

We add all the numbers together, and all the variables

1/x+3/x^2-(-1x+1)-2=0

We get rid of parentheses

1/x+3/x^2+1x-1-2=0

We calculate fractions

We do not support expression: x^3

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